Optimizing Angle for Shooting at a Distance with a Sniper Rifle
Thread startertaffman123
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In summary, the conversation involved a first-year university student seeking help with a question on shooting a rifle gun. They discussed using kinematic equations to calculate the angle needed to shoot an object on a building at a certain distance and height. The student also asked about using trigonometric identities to help with the calculations. They eventually got to the point of having a bi-quadratic equation, which they solved using trigonometric identities and substitution. The final answer was not provided.
Your are correct. You need to get the two trig functions in the same form (sin, cosine, sec, etc.), but at the moment I can't recall any useful trig identities.
hadeijv squared the whole equation, giving as topsquark says a bi-quadratic. This allowed himto use the ident [itex] \sin^2 x + \cos^2 x = 1 [/itex] to remove the sin and just leave cosine function.
Yes, you are both working on the same problem and using the same equations. Looking at the other thread may give you some hints. Topsquark explained it well.
#44
MrRottenTreats
18
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okay, I am trying to work this out I am at 1500sinx / cosx -15/cos2x - 40 = 0 ... and i do not know where to go form here. and is this correct?