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## Homework Statement

A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 22.0 m. She pushes in a direction 29° below the horizontal. A 48.0 N frictional force opposes the motion of the cart. What is the magnitude of the force that the shopper exerts?

## Homework Equations

F = mg

W = (F cosθ)s

## The Attempt at a Solution

1. F = (16kg)(9.8m/s

^{2}) = 156.8 N

2. F

_{N}= 156.8 N - 48.0 N = 108.8 N

Correct answer: 54.9 N

I know if you divide 108.8 by two you get 54.4 (which is really close to the answer), but I don't think you're supposed to divide by 2. Can someone help me out? :s