A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 22.0 m. She pushes in a direction 29° below the horizontal. A 48.0 N frictional force opposes the motion of the cart. What is the magnitude of the force that the shopper exerts?
F = mg
W = (F cosθ)s
The Attempt at a Solution
1. F = (16kg)(9.8m/s2) = 156.8 N
2. FN= 156.8 N - 48.0 N = 108.8 N
Correct answer: 54.9 N
I know if you divide 108.8 by two you get 54.4 (which is really close to the answer), but I don't think you're supposed to divide by 2. Can someone help me out? :s