# Homework Help: Short Work & Power Question.

1. Dec 9, 2006

### devinechels

Okay, I am really curious as to how you solve this question, I can't seem to figure it out. I am sure most of you will think it's a piece of cake, but I'm not a physics person at all :p

If the suitcase was lifted 0.75 meters, how much force was required? (Hint: Use the equation for "work")

But see, the equation for work is Work= force x distance...and so there is not enough information? I don't know, I just can't wrap my head around this one, I have been thinking about it for awhile, and now it's really bothering me. That would make my day if someone knew how to do it, thanks!

2. Dec 9, 2006

### devinechels

Oh wow, I feel dumb. It was a continuation of another question >.< so sorry. Okay, so the first question was "15 J/s of power were needed to lift a suitcase into the trunk of a car in 2.8 seconds. How much work was done?" for that, I got 5.4 J because 15 J/s divided by 2.8s which is W= p divided by t. So now, do I need to do F= w/d?

3. Dec 9, 2006

### Harmony

The second question can be solved without referring to the first.
Work Done = Change in Gravitational Potential Energy
Work Done = F*s
This two equation should be sufficient enough....