- #1
rhey
- 6
- 0
shortest distance??
find the shortest distance of y=x^2 from (4,0)
if y=x^2, then
y'=2x
where x=4
the slope is 8
the solution is
y=8(x-4)
if that is the tangent line \, the normal line would be
y=(1/8)(x-4)
after that.. I'm stuck!
Homework Statement
find the shortest distance of y=x^2 from (4,0)
Homework Equations
The Attempt at a Solution
if y=x^2, then
y'=2x
where x=4
the slope is 8
the solution is
y=8(x-4)
if that is the tangent line \, the normal line would be
y=(1/8)(x-4)
after that.. I'm stuck!