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Introductory Physics Homework Help
Show that the flywheel inside the train counteracts lean in a curve
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[QUOTE="TSny, post: 6242882, member: 229090"] I'm having some trouble understanding the description of your reasoning. As the carriage makes a left turn, the flywheel changes its orientation. The vector ## \mathbf M_G## is the torque ("moment of force") that must be applied to the flywheel in order to cause the flywheel to change its orientation. This torque comes from the supports at each end of the axis of the flywheel. These supports are attached to the walls of the carriage. So, ## \mathbf M_G## is the torque that the carriage applies to the flywheel. Therefore, the flywheel applies a [I]reaction torque[/I] of the same amount but in the opposite direction to the carriage. Thus, the flywheel exerts a torque ##- \mathbf M_G## to the carriage. You need to show that ##- \mathbf M_G## is in the direction that helps to prevent the carriage from tipping over [I]if ##\boldsymbol \omega_0## is in the positive x direction [/I](as shown in the figure). Is this how you are thinking about it? If you understand the solution up to the last line, then you understand that ## \mathbf M_G## is in the positive y-direction if ##\boldsymbol \omega_0## is in the positive x-direction. (The solution is based on the assumption that ##\boldsymbol \omega_0## is in the positive x-direction. See the third line of the solution and also the figure.) Therefore, ##- \mathbf M_G## is in the negative y-direction. Is this the correct direction in order to help prevent the carriage from tipping? [/QUOTE]
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Show that the flywheel inside the train counteracts lean in a curve
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