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Show the line of intersection of both planes by finding the coordinates of a point

  • Thread starter rainez
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  • #1
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Homework Statement



The planes ∏1 and ∏2 have equations 3x - y - z = 2 and x + 5y + z = 14 respectively. Show that the point (3,1,6) lies on both planes.

The Question:
By finding the coordinates of another point lying in both planes, or otherwise, show that the line of intersection of ∏1 and ∏2 has equation r = 3i + j + 6k + t ( i -j + 4k ).


Homework Equations



Show point (3,1,6) lies in both planes:
Substitute point (3,1,6) into the r of both plane equations.


The Attempt at a Solution



The first part:

Let point (3,1,6) be a

Substitute a into r of both plane equations.

The dot product of a and r = ''d" of the plane equations.
LHS=RHS [Shown]

How do I attempt the second part of the question? I do not quite understand the second part of the question.
Please help me. :uhh:
Thanks!
 

Answers and Replies

  • #2
LCKurtz
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Homework Statement



The planes ∏1 and ∏2 have equations 3x - y - z = 2 and x + 5y + z = 14 respectively. Show that the point (3,1,6) lies on both planes.

The Question:
By finding the coordinates of another point lying in both planes, or otherwise, show that the line of intersection of ∏1 and ∏2 has equation r = 3i + j + 6k + t ( i -j + 4k ).


Homework Equations



Show point (3,1,6) lies in both planes:
Substitute point (3,1,6) into the r of both plane equations.


The Attempt at a Solution



The first part:

Let point (3,1,6) be a

Substitute a into r of both plane equations.

The dot product of a and r = ''d" of the plane equations.
LHS=RHS [Shown]

How do I attempt the second part of the question? I do not quite understand the second part of the question.
Please help me. :uhh:
Thanks!
You just need to find x,y, and z that work in both equations. You have 2 equations in 3 unknowns, so it should be easy with an extra unknown. Try something like letting y = 0 and see if you can find an x and z that work.
 
  • #3
HallsofIvy
Science Advisor
Homework Helper
41,777
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Homework Statement



The planes ∏1 and ∏2 have equations 3x - y - z = 2 and x + 5y + z = 14 respectively. Show that the point (3,1,6) lies on both planes.

The Question:
By finding the coordinates of another point lying in both planes, or otherwise, show that the line of intersection of ∏1 and ∏2 has equation r = 3i + j + 6k + t ( i -j + 4k ).


Homework Equations



Show point (3,1,6) lies in both planes:
Substitute point (3,1,6) into the r of both plane equations.


The Attempt at a Solution



The first part:

Let point (3,1,6) be a

Substitute a into r of both plane equations.

The dot product of a and r = ''d" of the plane equations.
LHS=RHS [Shown]

How do I attempt the second part of the question? I do not quite understand the second part of the question.
Please help me. :uhh:
Thanks!
You are given planes 3x - y - z = 2 and x + 5y + z = 14 and want to show that their line of intersection is r = 3i + j + 6k + t ( i -j + 4k ).
Since you are given a line you don't have to solve for it, just check as you did for the point.

You have already shown that (3, 1, 6) is in both planes so all you now need to do is show that the vector i -j + 4k lies in both planes and so in the line of intersection. And you can do that by showing it is perpendicular to the normal vectors to both planes: 3i- j- k and i+ 5j+ k.
 

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