- #1

St41n

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So, β^n -> 0 as n -> infty

Also, we can find γ>1 so that

{γ^n}*{β^n} -> 0 as n -> infty

e.g. γ = β^{-(1/2)}

My question is how can i show that:

n*β^n -> 0 as n -> infty

and there exists γ>1 so that:

{γ^n}*{n*β^n} -> 0 as n -> infty

I appreciate any help