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Showing G is abelian

  1. Jan 14, 2012 #1
    Thanks I figured it out.
     
    Last edited: Jan 15, 2012
  2. jcsd
  3. Jan 14, 2012 #2
    Start with the identity (gh)^5 = g^5h^5, do what you can with inverses, then go to (gh)^3 = g^3h^3 and do the same, then see if you can make a substitution back into the first one, from here just see whats equal to what and play around for a bit with inverses, I didn't even need to use (gh)^4 = g^4h^4.
     
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