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Mathematics
Calculus
Showing that a sequence of supremums of a sequence has these two properties
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[QUOTE="Office_Shredder, post: 6474870, member: 53426"] For step 1, your proof is wrong because in general ##A_n## does not have to be equal to any of the ##a_i##s. For example if ##a_i=1+1/i## for all i, then ##A_n=1## for all n.Your proof really shouldn't involve any complicated inequalities. ##A_n## is an upper bound of the set that ##A_{n+1}## is the supremum of. Why? [/QUOTE]
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Forums
Mathematics
Calculus
Showing that a sequence of supremums of a sequence has these two properties
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