1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Shpae functions FEM

  1. Apr 4, 2012 #1
    1. The problem statement, all variables and given/known data
    http://img545.imageshack.us/img545/8149/13862239.png [Broken]

    The displacement functions:


    http://img256.imageshack.us/img256/2743/13939694.png [Broken]

    Derive the displacement functions 2-10 up to 2-13.

    2. Relevant equations
    Third cubic polynomial and elementary beam theory


    3. The attempt at a solution
    I don't understand how the displacement functions can be derived can somebody give me a hint?
     
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Apr 7, 2012 #2
    Hmmm, the title should read displacement functions. The thing is I know that [itex] \xi [/itex] should run between 0 and 1 (because [itex] \xi = x/L) [/itex]. But why is the displacement: [tex]y(0) =
    \theta_1 \cdot L [/tex] shouldn't there be a correction for the second angle? Moreover why is the displacement at the end zero e.g. why is y(1) =0?

    By the way the picture ends like this:

    http://img252.imageshack.us/img252/4352/31333995.png [Broken]

    ands starts like this:

    http://img341.imageshack.us/img341/4606/99014438.png [Broken]
     
    Last edited by a moderator: May 5, 2017
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Shpae functions FEM
  1. FEM problem (Replies: 0)

  2. A function (Replies: 19)

  3. Functions ? (Replies: 18)

  4. FEM with discontinuity (Replies: 2)

Loading...