(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

the questions quite big, but ill stick to the relevant parts

power at the load, 35000W

Voltage at load, 220V

cable resistance = 0.1ohm

field resistance = 60V

3. The attempt at a solution

the current at the load is P (load)/ V (load) = 35000/220 = 159A

the voltage drop from resistance, IR = 159x0.1 = 15.9V

terminal voltage is 15.9 + 220 = 235.9V

and so across the inductor - current (field) = V/R(field) = 235.9/60 = 3.93A

so now at this point, it asks for the armature current. which is calculated to be

159A + 3.93A = 163A

so here the current in armature is 163A yet the current at the load is 159A

there is only 1 cable the current can travel down, and to me it can either be 1 or the other.

can someone please explain any of this. any help greatly appreciated.

(by the way, these are the values calculated by my lecturer. he would give 100% on if you answered with these values)

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# Homework Help: Shunt motor

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