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Kryslynn
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Homework Statement
At lift off, the three main engines and the two booster rockets of the 4.5X106 lb space shuttle produced 6.4X106 lbs of thrust vertically downward. What was the acceleration at liftoff and assuming the acceleration remains constant how long did it take the shuttle to rise through its own height of 184 ft?
Homework Equations
S=So+V*t+1/2*a*t^2
V=Vo+a*t
The Attempt at a Solution
Fdown = 4.5 x 106 lb., F Thrust = 6.4 x 106 lbs.
lb. = slug x ft. /sec2
6.4 x 106 lbs - 4.5 x 106 lb = 1.9 x 106 lbs. upwards
F=mg --> m = f/g.
(1.9 x 106 lb.)/(32 ft./sec2) = 5.8 x 104 Slugs
F=ma --> a = f/m
V = 0 + 32 ft./sec2