Sig Fig Problem: Calculating t with I=3.20A, L=4.2m, etc

[Tcat]

In this one problem I am given I=3.20A, L=4.2m, cross-section=.00220m, n=8.85*10^28, and e=1.6*10^-19.
I am using an equation that is set up like this to find the t=((l*w)*n*q*L)/I
When I calculate ((0.00220m)^2*(8.85*10^28)(1.6*10^-19)*(4.2))/(3.2) I get 8.99*10^4 and for some reason the sig. figs are wrong! I don't know why?

 

[Tide]

Since L and e are given only to two significant figures your final answer should also be written to two significant figures.

 

[quicknote]

It appears that the incorrect number of significant figures is due to rounding errors in the calculation. When rounding each individual term in the equation to the correct number of significant figures, the final answer should be 8.99*10^4 seconds, or 89,900 seconds. However, it is always important to double check your calculations and make sure that you are using the correct number of significant figures throughout the entire equation to avoid any errors. Additionally, it may be helpful to show your work and include units in your calculations to ensure accuracy.