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## Homework Statement

A laser 632.8nm is sent through a single slit of widith 0.30 mm. Wats the width of the central maximum on a screen 1.0m in the back of the slit?

## Homework Equations

asin(theta) = m lamda

## The Attempt at a Solution

lamda: 632.8nm

0.30 mm= 3.0 x 10^-4 m

sin(theta)= m lamda/ a

sin(theta)= 1 (632.8x10^-9)/3.0 x 10^-4 m

= 2.10x10^-3 m