# Sign of moment

1. Jul 8, 2016

1. The problem statement, all variables and given/known data
in this notes, the shear force is negative because at LHS, shear force cause the beam to turn counterclockwise , am i right?
at RHS, the shear force cause the beam to turn anticlockwise, so that the shear force is also negative?

2. Relevant equations

3. The attempt at a solution

Why the moment change from -ve to +ve at the moment graph?
Is it wrong?
Shoudlnt the graph look like this? (red line)

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2. Jul 8, 2016

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3. Jul 8, 2016

### PhanthomJay

It is not wrong. The shear starts off negative and remains negative because therrre are no forces applied in between end points. Then from the calculus of beam theory, the slope of the moment diagram at a given point is equal to the shear at that point, so the slope of the moment diagram is always negative. The applied couple is a dicontinuity which adds a positive moment at that point.

4. Jul 8, 2016

can you explain in another way without the draw of moment and shear force graph ?
why the shear force is negative throughout the beam ? As we can see , the shear force acted upward at the left of beam , the shear force acted downward at the right of the beam ..... the sign convention that the author used are not consistent..... ( the assume upward as positive on the left , assume downward shear force as positive on the right . )
Is it wrong ?

5. Jul 8, 2016

### PhanthomJay

The reaction acts down at the left and up at the right. So by convention, the shear is downward negative starting at left, then stays constant negative because there is no load applied in between until the right end, then the reaction acts up there and thus the shear goes up back to 0.

6. Jul 8, 2016

So, shear force graph is " cumulative " ??

7. Jul 8, 2016

### PhanthomJay

Not sure what you mean by "cumulative.". The shear force is a constant value of -M_o/2L at any point along the beam between end points.

Last edited: Jul 8, 2016
8. Jul 8, 2016