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I am having trouble figuring this out mathematically...

I have no idea why but I can't figure it out using V=IR that the circuit on the left has 1/3 the current of the circuit on the right...

can anyone plz give a mathematical explaination?

Left : 3Vb = I1 * RL

Right : Vb = I2 * RL

then if Vb = 2 and RL = 1, wouldnt that make I1 > I2, by 3 times..

anyone suggestions?

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# Silly question

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