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Physics
Quantum Physics
Silly questions about the behaviour of photons
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[QUOTE="DrClaude, post: 5448871, member: 461323"] Basically, yes. You can't really talk about the temperature of light if it does not follow blackbody radiation. So red light is not "warmer" than blue light. In addition, blue light is actually [I]more[/I] energetic than red light, as energy goes as the inverse of the wavelength. This has nothing to do with intensity, which would be the amplitude of the electromagnetic wave in the classical picture, or number of photons in the quantum picture. You'll find plenty of threads on PF treating this subject. Unless you are looking at things like absorption of light by an individual atom, keeping it to the classical picture of an EM wave is much better. I don't understand what "pure" energy means. What would electromagnetic radiation by purer energy than gravitational potential energy? First, I guess you mean photons, not protons. Heat is not only kinetic energy. If you take for example a molecule of nitrogen, it stores heat as translational, vibrational, rotational, and electronic energy. But for symmetry reasons, it actually doesn't emit any radiation at normal temperatures (i.e., where electronic excitation is negligible). You, on the other hand, emit infrared radiation, mainly due to the vibration of the molecules that you are made of. As these vibrations involve the motion of electrically charged particles (protons and electrons), they can lead to emission of EM radiation. [/QUOTE]
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Silly questions about the behaviour of photons
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