I tried this question multiple times, but now I've become stuck. A person shoots a gun straight up into the air on New Year's Eve. The velocity at which the bullet leaves is 3.00 x 10^2 m/s. What is the maximum altitude of the bullet? Here's what I've tried: I attempted to apply the x=1/2(vi+vf)t formula, but it's missing some variables, namely vf, t, and the displacement. I've also tried to find the final velocity through vf=vi+at, but then I'm missing the time. Then I tried to get the final velocity with vf^2=vi^2+2ax, but I'm now missing the displacement. I must be not seeing something very obvious here. EDIT: Ahh...gods. I have just realized something. vf = 0 when the bullet reaches the top. Silly me--that means it's not missing any variables.