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Homework Help: Simple Algebra Question

  1. Nov 17, 2008 #1
    I know this is not an algebra forum but this problem arose for me in physics.

    Determine a numerical value for x:

    ((9^3)/27) = ((SQRT(24^4))/(3^x))

    I move the 27 to the top and the 3^x to the top and then solve for x this way.

    3 - 1 = 2 - x, this makes x equal to 0 but it is not right. What is the correct way to do this?

    Also, determine x for: 3^2x = 7(3^x)

    I used logs: 2xlog3=7(xlog3) The xlog3 will cancel and I can't solve for x anymore. Any recommendations?
  2. jcsd
  3. Nov 17, 2008 #2


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    Homework Helper

    I would isolate the 3x to one side of the equation by itself. Do you see what to do then?

    Try combining the terms algebraically first so that you only have one x in the equation.
  4. Nov 18, 2008 #3
    Complete Solution Removed
  5. Nov 18, 2008 #4
    I solved the first problem and got 3, which is the correct answer.. Thanks.

    I am still having problems with the next one. Do you divide both sides by 3^x and solve for x
  6. Nov 18, 2008 #5


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    Yes, that's what I would do.
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