I know this is not an algebra forum but this problem arose for me in physics.(adsbygoogle = window.adsbygoogle || []).push({});

Determine a numerical value for x:

((9^3)/27) = ((SQRT(24^4))/(3^x))

I move the 27 to the top and the 3^x to the top and then solve for x this way.

3 - 1 = 2 - x, this makes x equal to 0 but it is not right. What is the correct way to do this?

Also, determine x for: 3^2x = 7(3^x)

I used logs: 2xlog3=7(xlog3) The xlog3 will cancel and I can't solve for x anymore. Any recommendations?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Simple Algebra Question

**Physics Forums | Science Articles, Homework Help, Discussion**