I know this is not an algebra forum but this problem arose for me in physics. Determine a numerical value for x: ((9^3)/27) = ((SQRT(24^4))/(3^x)) I move the 27 to the top and the 3^x to the top and then solve for x this way. 3 - 1 = 2 - x, this makes x equal to 0 but it is not right. What is the correct way to do this? Also, determine x for: 3^2x = 7(3^x) I used logs: 2xlog3=7(xlog3) The xlog3 will cancel and I can't solve for x anymore. Any recommendations?