Yes, that wouldn't help anything. You just multiply both sides with it, and when you multiply a fraction with a factor, it's always in the nominator. c * a/b = ca/b.
You do this to get rid of the v_w in the denominators since you can cancel them out when they're also in the numerators.
You can try simplify the equation a bit:
[tex]\frac{300}{5v_w + 10} + \frac{300}{3v_w} = 8[/tex]
[tex]\Leftrightarrow \frac{60}{v_w + 2} + \frac{100}{v_w} = 8[/tex]
Then, you can try multiplying both sides with v_{w}(v_{w} + 2) to get rid of the denominator. And you will have:
[tex]60v_w + 100(v_w + 2) = 8v_w(v_w + 2)[/tex]
You can rearrange a bit, and you will have a quadratic equation.
Can you go from here?
Viet Dao,
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