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Simple algebra simplification SOLVED!

  1. Feb 28, 2012 #1
    1. The problem statement, all variables and given/known data
    2hd8a2o.png

    2. Relevant equations
    a^2-b^2 = (a+b)(a-b)
    a^2-2ab+b^2 = (a-b)(a-b)
    a^2+2ab+b^2 = (a+b)(a+b)

    3. The attempt at a solution

    SOLVED IT! Look at the bottom!

    With my first try i got the answer 0
    The result of first parenthesis was 1 /(√x+√y)

    From there on it went like this 1 /(√x+√y) - 1 /(√x+√y) = 0

    I'm suspecting that i might have messed up the order of operations, but not sure. I did the calculation inside the paranthesis first, then reversed it (^-1)

    The answer should come like this
    (2√y)/(x-y)

    Solution:
    Should be more careful next time.. i made an error when writing it down for myself. :) Now, with the correct signs i got

    1 /(√x-√y) from the first paranthesis, and from there on it was all piece of cake. Thanks.
     
    Last edited: Feb 28, 2012
  2. jcsd
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