a^2-b^2 = (a+b)(a-b)
a^2-2ab+b^2 = (a-b)(a-b)
a^2+2ab+b^2 = (a+b)(a+b)
The Attempt at a Solution
SOLVED IT! Look at the bottom!
With my first try i got the answer 0
The result of first parenthesis was 1 /(√x+√y)
From there on it went like this 1 /(√x+√y) - 1 /(√x+√y) = 0
I'm suspecting that i might have messed up the order of operations, but not sure. I did the calculation inside the paranthesis first, then reversed it (^-1)
The answer should come like this
Should be more careful next time.. i made an error when writing it down for myself. :) Now, with the correct signs i got
1 /(√x-√y) from the first paranthesis, and from there on it was all piece of cake. Thanks.