20 ml of decinormal HCl soln. is added to 10 ml decinormal AgNO3 soln. AgCl is precipitated out and excess of acid was back titrated against a decinormal NaOH soln., What volume of NaOH was required for the back titration?
2. The attempt at a solution
10 ml HCl reacts with 10 ml AgNO3. 10 ml HCl is left. Now Do we consider HNO3 formed also, since then it'd require 20 ml NaOH. If we consider only HCl it'd be 10