- #1
Mivz18
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Problem: The consumption of natural gas by a company satisfies the empirical equation V=1.50t + 0.800 00(t squared), where V is the volume in millions of cubic feet and t the time in months. Express this equation in units of cubic feet and seconds. Assign proper units to the coefficients. Assume a month is equal to 30.0 days.
My work:
From the equation given, I took each part of the right and converted the months variable to seconds.
1.50(t months) * (t 30 days) * (t 24 hours) * (t 60 min) * (t 60 sec.)
-------------- ---------- ---------- --------- ----------
1 (t month) (t 1 day) (t 1 hr.) (t 1 min)
= 3.888E6(t sec.)
Then I repeated the conversion multiplication fractions with 0.008 00 and squaring the other numbers and reaching a value of 5.37477E9(t sec)^2
My new equation is then V= 3.888E6(t sec.) + 5.37477E9(t sec.)^2
dividing by a million to convert millions of cubic feet to cubic feet, I get:
V=3.889E6(t sec.) + 53747.7(t sec.)^2
However, the book gives an answer of 0.579t (ft cubed/sec.) + 1.19E-9t^2 (ft cubed/sec. squared)
Is not assigning units to the coefficients screwing me up or is there another problem with my calculations?
My work:
From the equation given, I took each part of the right and converted the months variable to seconds.
1.50(t months) * (t 30 days) * (t 24 hours) * (t 60 min) * (t 60 sec.)
-------------- ---------- ---------- --------- ----------
1 (t month) (t 1 day) (t 1 hr.) (t 1 min)
= 3.888E6(t sec.)
Then I repeated the conversion multiplication fractions with 0.008 00 and squaring the other numbers and reaching a value of 5.37477E9(t sec)^2
My new equation is then V= 3.888E6(t sec.) + 5.37477E9(t sec.)^2
dividing by a million to convert millions of cubic feet to cubic feet, I get:
V=3.889E6(t sec.) + 53747.7(t sec.)^2
However, the book gives an answer of 0.579t (ft cubed/sec.) + 1.19E-9t^2 (ft cubed/sec. squared)
Is not assigning units to the coefficients screwing me up or is there another problem with my calculations?