Hello all. Really quick question here....What are the intervals of increase and decrease for y= e^x = e^-2x. I found the first derivative : y'= e^x-2e^-2x and set it equal to 0 but that's where I got stuck. How would you solve for x? I know that the answer is (ln2)/3 but how would you get there? Thanks.(adsbygoogle = window.adsbygoogle || []).push({});

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# Homework Help: Simple Calculus question

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