There exists a potential difference V between the plates of a parallel plate capacitor of capacitance C. Now it is connected to a cell with potential V. What will be the heat generated?
Work(on battery) - (energy stored in Capacitor) = Heat produced
The Attempt at a Solution
My logic was that since both have potential V, no charges will flow, but the answer is 2C(V)^2 ; can someone please explain? Thank you