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Simple capacitance

  1. Jun 4, 2007 #1
    Three capacitors of capacitance 5, 7, and 2 mF respectively, are connected in series to a 1 V battery. What is the charge on the positive plate of the 7 mF capacitor?

    so if the capacitors are all connected to the battery... than all of them have to have a electrial potential of 1 v

    since C=Q/V, then CV=Q

    and then i have (7 x10^-6 F)*1V=Q which is 7x10^-6 C

    that is what i am getting, but it seems to be wrong. please help me out
  2. jcsd
  3. Jun 4, 2007 #2


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    The capacitors are in series, so there is no requirement that they must have the same voltage across them.

    - Warren
  4. Jun 4, 2007 #3
    ok i got it.
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