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## Homework Statement

A capacitor connected to a battery initially holds a charge of +q on its positive plate and -q on its negative plate. The electric field between the plates is initially E. A dielectric material is then inserted that polarizes in such a way as to produce an electric field of -0.30E (where the - sign indicates that this field opposites that of E). Determine the new charge stored on the positive plate.

## Homework Equations

Eo-E=Ef

E=kq^2/r^2

## The Attempt at a Solution

I did my work on Word using the equation tool just to make the notation format easier to read.

Is my logic correct here?

Any help would be greatly appreciated! :)