Find the voltage V and the power absorbed by the 12-ohm resistor.
p = vi
v = ir
The Attempt at a Solution
Tried using KVL and KCL in various ways. This book gives horrid examples.
I found the current in the last loop to be .4 A. Using V = IR to solve to get the voltage, I get 4.8 V at the 12-ohm resistor. I then used P = VI to get a power of 9.6 W, but the book has 1.92 W. Did I do anything wrong or is the book wrong again?