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Simple collisions

  1. Oct 16, 2009 #1
    elastic collision in one dimension
    1. The problem statement, all variables and given/known data

    Block 1 of mass m1 slides along an x axis on a frictionless floor with a speed of 2.40 m/s. Then it undergoes a one-dimensional elastic collision with stationary block 2 of mass m2 = 2.00m1. Next, block 2 undergoes a one-dimensional elastic collision with stationary block 3 of mass m3 = 2.00m2.

    what is the speed of block 3? the answer is 1.78.

    i just can't figure it out.


    more questions that relate to problem...are the speed, kinetic energy, and the momentum of block 3 greater than or less than, or th same as the initial values for block one?

    the answers are less, less, greater...

    but i don't need help with them because i haven't attempted them yet.

    2. Relevant equations

    v1f = m1 - m2 / m1 + m2 * v1i

    v2f = 2m1 / m1 + m2 *v1i

    3. The attempt at a solution

    v1f = v2i = m1 - m2 / m1 + m2 * v1i
    = m - 2m/ m + 2m *4
    = -m/3m * 4
    = -4/3

    v2f = v3i = 2m1 / m1 + m2 * v1i
    = 2m / m +2m *4
    =2/3 *4
    =8/3

    v3f = m2 - m3 / m2 + m3 * v2i
    = 2 - 4 / 2 + 4 * (-4/3)
    = -2/6 (-4/3)
    =-8/18

    clearly this is wrong. i really did try a lot of different things. what am i doing wrong?

    when i multiply (4/3) by (8/3) and divide by 2, i get the right answer! but that's just luck.
     
  2. jcsd
  3. Oct 16, 2009 #2

    rl.bhat

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    Follow munchy35's post.
     
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