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Simple Contour Integral

  1. Aug 12, 2014 #1
    1. The problem statement, all variables and given/known data
    |z| = 2, [itex]\oint\frac{1}{z^3}[/itex]

    2. Relevant equations
    Cauchy's Integral Formula

    3. The attempt at a solution
    Seems like a simple application of the general formula on the wiki page with n = 2, a = 0, and f(z) = 1. The higher order derivatives just yield zero, making the integral zero. Just asking for verification for a friend.
  2. jcsd
  3. Aug 12, 2014 #2


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    Homework Helper

    You're using a circle of radius 2 as a contour. You could parametrize it with some ##z(t)##, and then evaluate it. Think about ##e##, and see what you get.
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