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Simple derivation of the Equations of a Gyroscope
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[QUOTE="PeroK, post: 6113109, member: 493650"] There's a critical point at 2:25 where he equates the torque generated by the vertical forces to a torque generated by horizontal forces. That equivalence would appear to require that the wheel is supported by a rigid joint with the rope. In which case that equivalence would apply to a non-spinning wheel as well. Why can he equate the different torques for a spinning wheel but not for a non-spinning wheel? That would be my question. Edit: to answer my own question, it doesn't require the rigid joint. In the case of the static wheel, the wheel rotates and falls; and, in the case of the spinning wheel, the wheek precesses. And the faster the wheel is spinning the more pronounced the precession and the less pronounced the falling. [/QUOTE]
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Simple derivation of the Equations of a Gyroscope
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