# Simple derivative problem

ln (2x^2 + 3)

ln 2x^2 + ln 3

## The Attempt at a Solution

(4x/2x^2) + (3/3)
(2x/x^2) + 1

I know this is a simple problem but what is the derivative of ln3? Is it 1 (3/3) or 0?

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properties of logs

$$\ln(ab)=\ln(a)+\ln(b)$$

what you have is

$$\ln(a+b)=\ln(a+b)$$

example

$$\ln(x^{2}+3)$$

differentiating

$$\frac{2x}{x^{2}+3}$$

Last edited:
example

$$\ln(x^2)$$

differentiating

$$\frac{2x}{x^2}$$

properties of logs

$$\ln(ab)=\ln(a)+\ln(b)$$
Can't you distribute the ln to get lna + lnb? I don't know what the derivative of ln3 is? Is it 3/3 or 0/3.

Can't you distribute the ln to get lna + lnb? I don't know what the derivative of ln3 is? Is it 3/3 or 0/3.
i just updated my post, i clicked submit on accident while trying to preview.

Oh okay I see now. So it would be...
(4x)/(2x^2 + 3)
(2x)/(x^2 + 3)