- #1

- 2

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(x+3)(x-4)(x+5)

I've tried using the product rule on the first two and then using the rule on the result from that and (x+5) but it's not working. I'm an idiot.. thanks for any help.

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- Thread starter sbose27
- Start date

- #1

- 2

- 0

(x+3)(x-4)(x+5)

I've tried using the product rule on the first two and then using the rule on the result from that and (x+5) but it's not working. I'm an idiot.. thanks for any help.

- #2

- 2,076

- 2

- #3

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okay thanks a lot

- #4

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I've tried using the product rule on the first two and then using the rule on the result from that and (x+5) but it's not working.

That should work actually.

If you call the 3 functions u(x), v(x) and w(x) and let y(x) = u(x)v(x), then [y(x)w(x)]' = y'w + yw'. Just replace y = uv and y' = u'v + uv', you get (u'v + uv')w + uvw' = u'vw + uv'w + uvw', which is exactly what neutrino.

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