1. Mar 15, 2007 #1

   sbose27

   

   Sorry for not using JavaScript or whatever script is needed, I don't have enough time to figure it out b/c my class is soon... anyways I just need to know know to find the derivative of 3 groups of parentheses
   
   (x+3)(x-4)(x+5)
   
   I've tried using the product rule on the first two and then using the rule on the result from that and (x+5) but it's not working. I'm an idiot.. thanks for any help.

    

   sbose27, Mar 15, 2007
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Game over? Computer beats human champ in ancient Chinese game
   • • Simplifying solar cells with a new mix of materials
   • • Imaged 'jets' reveal cerium's post-shock inner strength
3. Mar 15, 2007 #2

   neutrino

   

   It's a simple extension of the product rule: (uvw)' = u'vw + uv'w + uvw', where u,v and w are functions of x.

    

   neutrino, Mar 15, 2007
4. Mar 15, 2007 #3

   sbose27

   

   okay thanks a lot

    

   sbose27, Mar 15, 2007
5. Mar 15, 2007 #4

   end3r7

   

   That should work actually.
   If you call the 3 functions u(x), v(x) and w(x) and let y(x) = u(x)v(x), then [y(x)w(x)]' = y'w + yw'. Just replace y = uv and y' = u'v + uv', you get (u'v + uv')w + uvw' = u'vw + uv'w + uvw', which is exactly what neutrino.

    

   end3r7, Mar 15, 2007

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in