Simple Derivative Question

  • Thread starter sbose27
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  • #1
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Sorry for not using JavaScript or whatever script is needed, I don't have enough time to figure it out b/c my class is soon... anyways I just need to know know to find the derivative of 3 groups of parentheses

(x+3)(x-4)(x+5)

I've tried using the product rule on the first two and then using the rule on the result from that and (x+5) but it's not working. I'm an idiot.. thanks for any help.
 

Answers and Replies

  • #2
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It's a simple extension of the product rule: (uvw)' = u'vw + uv'w + uvw', where u,v and w are functions of x.
 
  • #3
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It's a simple extension of the product rule: (uvw)' = u'vw + uv'w + uvw', where u,v and w are functions of x.
okay thanks a lot
 
  • #4
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I've tried using the product rule on the first two and then using the rule on the result from that and (x+5) but it's not working.
That should work actually.
If you call the 3 functions u(x), v(x) and w(x) and let y(x) = u(x)v(x), then [y(x)w(x)]' = y'w + yw'. Just replace y = uv and y' = u'v + uv', you get (u'v + uv')w + uvw' = u'vw + uv'w + uvw', which is exactly what neutrino.
 

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