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I am just starting out in calculus, and I'm not sure how to work through this type of question:

f' [tex]\frac{3x-6}{x}[/tex]

So I have:

(3x-6)(x[tex]^{-1}[/tex])

then (3x -6)(-x[tex]^{-2}[/tex])

Now what?

(3)(-x[tex]^{-2}[/tex])?

The book gives an answer of 6(x[tex]^{-2}[/tex])

Thanks in advance

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# Homework Help: Simple derivative

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