# Simple derivative

#### nameVoid

D= (x^2+x)^(1/2)

I have a solutions manual here showing
D' = (1/2)(x^2+x)^(-1/2) (2x+1)(x')
but correct me if im wrong..
D' = (1/2)(x^2+x)^(-1/2) (2x+1)(2x')

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#### rock.freak667

Homework Helper
well you didn't state what you were taking derivatives with respect to.

But if you have D(t)=f(x)

then D'(t)=f'(x)* (dx/dt) = f'(x)*x'

In your question; $f(x)=\sqrt{x^2+x}$

#### nameVoid

differentiating with respect to time t if you could please answer this simple question directly i would be glad especialy

#### Mark44

Mentor
D= (x^2+x)^(1/2)

I have a solutions manual here showing
D' = (1/2)(x^2+x)^(-1/2) (2x+1)(x')
but correct me if im wrong..
D' = (1/2)(x^2+x)^(-1/2) (2x+1)(2x')
The first one is correct; the second one is incorrect.

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