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Simple derivative

  1. Mar 30, 2009 #1
    D= (x^2+x)^(1/2)

    Why does the chain rule in this case produce D' = (1/2)(x^2+x)^(-1/2) (2x+1)(x')

    and not D' = (1/2)(x^2+x)^(-1/2) (2x+1)(2x')
  2. jcsd
  3. Mar 30, 2009 #2


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    [tex]\frac{dD}{dt}=\frac{dx}{dt} \times \frac{dD}{dx}[/tex]

    So like in the other thread, can you understand why now?
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