- #1
cscott
- 782
- 1
How do I deal with the square root in [itex]y = \sqrt{x}(x - 1)[/itex]?
Jameson said:Oh, ok. You were righting a mixed fraction. It would be best to call 1.5 [tex]\frac{3}{2}[/tex]
Try not to use mixed fractions, they get too confusion. Use improper ones.
The formula for the derivative of Y = √x(x-1) is:
Y' = (1/2√x) * (x-1) + (√x) * (1)
Y' = (√x - 1)/(2√x)
To find the derivative of a square root function, use the following formula:
f'(x) = 1/(2√x) * f(x)
The rule for finding the derivative of a product of two functions is the product rule:
(fg)' = f'g + fg'
Yes, the derivative of Y = √x(x-1) can be simplified to:
Y' = (√x - 1)/(2√x)
The derivative of Y = √x(x-1) can be used in many real-world applications, such as calculating the rate of change in a system, determining maximum and minimum values, and solving optimization problems.