1. The problem statement, all variables and given/known data y ' [x] = xy y = 1 2. Relevant equations none 3. The attempt at a solution I posted this somewhere else and 2 people got the answer is y = e^x I am getting something else though. I get up to here: dy/dx = xy 1/y dy = x dx ln y = (x^2)/2 + C that is what i get to, but here is what the other person got from this point: y = e^[ (x^2/2) + C ] (Im not confused on e^ln^y = y fyi) then he simplified that to: y = Ce^x (I DONT understand that property of natural logs) 1 = C * e^0 C = 0 y = e^x anyone care to explain? dont worry if you know a better way and start from scratch, ignore mine and this other guys answer if you want.