- 18

- 0

**1. Homework Statement**

Suppose a fluid is flowing down a pipe that has a circular cross-section of radius a. Assuming that the velocity V of the fluids depends only on its distance from the centre of the pipe, the equation satisfied by V is

(1/r)(d/dr)(r dV /dr) = -P where P is a positive constant

Find the expression for velocity given that:

1. The velocity should be finite at all point in the pipe/

2. Fluid "sticks" to boundaries (V(a) = 0 )

Show that:

V(r) = P/4 (a^2 - r^2)

**3. The Attempt at a Solution**

I integrate the first time to get:

dV/dr = -Pr/2 + c/r

and integrate again to get (FTC)

V(r) - V(a) = (-Pr^2 / 4) + C ln r [with lower bound a and upper r]

To show what I needed, it seems I only needed to get rid of that second term, but I'm unsure what assumption can justify that and where it applies.