- #1

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I just find it difficult to get started on this, I seem not able to separate out the variables dV and x. Thanks for the help.

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- Thread starter John O' Meara
- Start date

- #1

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I just find it difficult to get started on this, I seem not able to separate out the variables dV and x. Thanks for the help.

- #2

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- #3

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Do I write down x^2V' =0, then [tex] x^2 \int dV =0 [/tex]

- #4

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No, you write

[tex]x^2\frac{dV}{dx} = k(constant)[/tex]

[tex]x^2\frac{dV}{dx} = k(constant)[/tex]

- #5

Office_Shredder

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EDIT: Bah, I screwed up somewhere in the latex. arunbg wrote the essential part anyway

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- #7

cristo

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You can't separate the original equation like that. You have [tex]\frac{d}{dx}\left(x^2V'\right)=0[/tex]. Integrating both sides wrt x gives [tex]\int \frac{d}{dx}\left(x^2V'\right)dx=k \Rightarrow x^2V'=k[/tex]

Your next part is correct. Now integrate that.

Your next part is correct. Now integrate that.

Last edited:

- #8

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Thanks cristo for your help.

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