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Homework Help: Simple differential equation

  1. Mar 4, 2008 #1
    1. The problem statement, all variables and given/known data
    i'm trying to solve the simple differential equation y'=(x+xy^2)


    2. The attempt at a solution

    i get dy/(1+y^2)=xdx and then integrate over the whole thing getting the solution

    arctan(y)=0.5x^2+C

    my problem is how do i simply this down to an equation in the form y=...

    i must be missing something
     
  2. jcsd
  3. Mar 4, 2008 #2
    well remember that if [tex]tan(x)=y[/tex] then [tex]arctan(y)=x[/tex] does this help u? Tan and arctan are inverse functions so, tan(arctan x)=x
     
    Last edited: Mar 4, 2008
  4. Mar 4, 2008 #3
    but that x only valid under certain bounds right? and i'm having trouble figuring out what those are
     
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