The problem is Solve the following differential equation: dy/dx = 6*x*y/(3-x^2)
Okay so I know the first step is integrating both sides and separating the variables
The Attempt at a Solution
So separating the variables and integrating I get integral of \int y*dy \ = integral of
\int (6x)/(3-x^2) \, dx
Using substation for the the x variable I get -3ln(-x^2+3) +c and for the y variable as just y(x).
Now after this what is the next step. Should i rewrite the log natural as 1/(x^2-3)^2?