1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple Diode Circuit Analysis

  1. Sep 12, 2009 #1
    1. The problem statement, all variables and given/known data

    Attached is the homework problem I'm having difficulty with. I need to sketch vout for the circuit, assuming the diode ON voltage is 0.6 V. I'm stuck at how to begin this problem.

    2. Relevant equations



    3. The attempt at a solution
    It's only the 2nd week of class so I'm not too good with this, and I'm a bit rusty with my circuits as it is. My initial idea was to find the current going in the circuit but I'm just absolutely confused by this question. I don't understand why there are voltage sources after the diodes and what that does to the circuit. I also get confused with how I should find the current with an AC voltage source. Any guidance in the correct direction would be greatly appreciated.
     

    Attached Files:

    • hw1.doc
      hw1.doc
      File size:
      32.5 KB
      Views:
      127
  2. jcsd
  3. Sep 12, 2009 #2

    CEL

    User Avatar

    The diodes will conduct when the voltage at their anodes is 0.6V above the voltage at their cathodes.
    While neither diode is conducting, there is no current, so, no voltage drop at the resistor.
     
  4. Sep 12, 2009 #3
    Okay, that makes sense. What do the DC voltage sources after the cathodes do to the circuit?
     
  5. Sep 13, 2009 #4

    CEL

    User Avatar

    They assure that the diodes will fire only when the AC source voltage is 0.6V over or below the voltages of the DC sources.
     
  6. Sep 13, 2009 #5

    Redbelly98

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    Depending on what Vin is, each diode can act like either a 0.6V voltage source or like an open circuit (i=0).

    For example, if the left-hand diode is at 0.6V, that would add to the battery there to give Vout=____?
     
  7. Sep 13, 2009 #6
    I actually figured out that the circuit was a clipping circuit. The sketch will oscillate between +5.6V and -8.6V. For some reason I wasn't able to recognize the circuit! Thanks for all the help!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Simple Diode Circuit Analysis
  1. Simple Diode Circuit (Replies: 0)

  2. Diode circuit analysis (Replies: 7)

  3. Diode circuit analysis (Replies: 2)

Loading...