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Simple domestic electricity

  • Thread starter hgo0
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  • #1
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A current of 0.25A flows through a bulb when a voltage of 12V is applied across it. Calculate the power and resistance of the bulb.

please show working out
 

Answers and Replies

  • #2
tiny-tim
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Welcome to PF!

Hi hgo0! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
  • #3
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0.25A x 12V = 3W

i dont know how to get the resistance or if im doing this right :uhh:
 
  • #4
tiny-tim
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0.25A x 12V = 3W
Hi hgo0! :smile:

That's right: amps times volts = watts (or current times voltage = power).
i dont know how to get the resistance or if im doing this right :uhh:
Have you done Ohm's Law (or Kirchhoff's rules ) ? If not, look them up.

V = IR (or potential difference = voltage = current times resistance). :wink:
 
  • #5
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kk thanks alot i'm new to physics (first year) and failing soo i need all the help i can get :biggrin:
 

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