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Simple electrochem prob

  1. Jun 9, 2009 #1
    An electrochemical cell of notation Pd|Pd2+ || Ni2+ |Ni has Eo = -1.45 V. If we know that the standard reduction potential of Ni2+ /Ni is Eo = -0.25 V, what is the standard reduction potential for Pd2+/Pd?

    hey guys. this is my working
    Ecell=reduction-oxidation
    therefore Pd is anode therefore oxidisin and Ni is cathode therefore reducin.
    so i sub this into formula -1.45=-0.25-oxidation therefore oxidation=-1.20 however the answer is positive 1.20, why is this? anyhelp would be good thanks
     
  2. jcsd
  3. Jun 9, 2009 #2
    Hello there,

    This can be considered as a "tricky" question. I did not arrive at the right answer on my first try.

    You have to read the question carefully. Although you calculated the standard OXIDATION potential for Pd -> Pd2+ + 2e- correctly, you are asked for this half-reaction's standard REDUCTION potential (and NOT oxidation potential). Therefore, the correct answer is -(-1.20) = 1.20.

    I hope that this helps!
     
  4. Jun 9, 2009 #3
    thanks mate, cleared that problem up good. thanks again
     
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