1. Sep 20, 2005 #1

   Stevecgz

   

   Question:
   The reaction of 1.36 g of manganese with excess cholrine produced 4.00 g of chloride compound of manganese. Determine the empirical formula of the product.
   
   If I calculate this with cholrine as [tex]Cl_{2}[/tex] I get [tex]Mn_{3}Cl_{4}[/tex].
   
   But if I calculate it with cholrine as [tex]Cl[/tex] I get [tex]Mn_{3}Cl[/tex].
   
   Which way is correct?
   
   Steve

    

   Stevecgz, Sep 20, 2005
2. 
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3. Sep 20, 2005 #2

   HallsofIvy

   

   Staff Emeritus

   Science Advisor

   How do you get those two answers? Since you start with 1.36 g of manganese and end with 4 g of compound, there must be 4- 1.36 = 2.64 g of chlorine atoms in the compound. 1.36 g is how many manganese atoms? 2.64 g of chlorine is how many chlorine atoms? What is the ratio?

    

   HallsofIvy, Sep 20, 2005
4. Sep 21, 2005 #3

   Stevecgz

   

   Doh! Dyslexia kicking in again. Thanks HallsofIvy, I found where I messed up now.
   
   Steve

    

   Stevecgz, Sep 21, 2005

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