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Simple equation

  1. May 4, 2006 #1
    Hi i need a little help with an equation

    Ber=1/2*exp(-rT)
    I want to solve it to -rT
    Which of the following solutions is correct?
    ln(BER/2)=-rT or
    ln(BER/2)=rT
     
  2. jcsd
  3. May 4, 2006 #2

    J77

    User Avatar

    Neither...

    First, exp(-rT)=2*Ber

    I think you can do the rest and remember to show respect to that minus sign :smile:
     
  4. May 4, 2006 #3
    No i dont remember how to do it :(
    What i know it that
    exp(x)=theta
    ln(theta)=x
     
  5. May 4, 2006 #4

    J77

    User Avatar

    [tex]2B=e^{-rT}\implies ln(2B)=-rT[/tex]

    If you want to go further...

    [tex]aln(x)=ln(x^a)[/tex] can be used
     
  6. Jan 26, 2008 #5
    iam ph.d studentin electrical enginerring/USM/MALYSIA
    Ihave some equestion
    1-my research :new noise measurement techniques sing it error rate,iwant ask how make the relation ship betwen BER,NF LINERITY
    2-CAN HELP ME FOR FIND NEW EQUATION OF BER RELATED TO NF
    THANK U VERY MUCH FOR HELP ME
    EKHLAS KADHUM
    ekhlas_kadhum@yahoo.com
     
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