# Simple Formula Manipulation

1. Dec 8, 2007

### Sucks@Physics

I'm trying to find the intensity of something. I know the equation is

B = 10log(I/Io)

But how to I solve for I? What would the equation be? For some reason I can't make it work.

2. Dec 8, 2007

### Staff: Mentor

logarithms

Does this help?
If $$a = log(b)$$

then $$b = 10^a$$

3. Dec 8, 2007

### Sucks@Physics

No, i still can't ge thte correct equation, i come up with something like (10x10^B)/Io

4. Dec 8, 2007

### l46kok

Rewrite the equation as
I/I0 = 10^(B/10)

Last edited: Dec 8, 2007
5. Dec 8, 2007

### Staff: Mentor

Not quite:
B = 10log(I/Io)
B/10 = log(I/Io)
10^(B/10) = I/Io
I = Io*10^(B/10)

6. Dec 8, 2007

### Sucks@Physics

Thanks, that is kinda tricky, but now i understand it

7. Dec 8, 2007

### l46kok

From the provided information, Doc Al's equation is correct. You may be using wrong values for your Io and B, or your intensity equation could be incorrect.