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Simple FORTRAN question

  1. Jun 11, 2008 #1
    I want Fortran to regconize trigonometric functions.

    The trigonometric equation I am trying to right in Fortran is the Law of cosines

    COS(c)=d^2+a^2-b^2/(2*a*d)
    However, I want Fortran to calculate the inverse of the above equation:

    How would I write the following equation in Fortran?
    c=COS^1-(d^2+a^2-b^2/(2*a*d))
     
  2. jcsd
  3. Jun 11, 2008 #2

    Borek

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    Staff: Mentor

    You are looking for arccos - you will have to check documentation for the correct name of the function, as it differs between dialects.
     
  4. Jun 11, 2008 #3

    alphysicist

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    Homework Helper

    Hi Benzoate,

    The inverse cosine function is given by:

    acos()
     
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