1. The problem statement, all variables and given/known data Two students are on a balcony 23.5 m above the street. One student throws a ball, b1, vertically downward at 14.1 m/s. At the same instant, the other student throws a ball, b2, vertically upward at the same speed. The second ball just misses the balcony on the way down. (a) What is the difference in time the balls spend in the air? (b) What is the velocity of each ball as it strikes the ground? (c) How far apart are the balls 0.520 s after they are thrown? 2. Relevant equations d=vt d=.5(v0+vf)t d=v0t+ .5at^2 3. The attempt at a solution I found the time it took for the first ball to hit the ground using the first formula vt=d 14.1t=23.5 t=1.7 seconds Next, I tried to find the time it took the second ball to hit the ground using the third equation d=v0t+ 5at^2 47=14.1t+(4.9)t^2 I am stuck here.. I just need some guidance on how to find the time it took the second ball to hit the ground and I can figure everything else out from there, hopefully. Thanks!